0 x 9 + 1 = 1 1 x 9 + 2 = 11 12 x 9 + 3 = 111 123 x 9 + 4 = 1111 1234 x 9 + 5 = 11111 12345 x 9 + 6 = 111111 123456 x 9 + 7 = 1111111 1234567 x 9 + 8 = 11111111 12345678 x 9 + 9 = 111111111 123456789 x 9 + 10 = 1111111111

SECOND: MAGIC OF 37

37 X 3 = 111 37 x 6 = 222 37 x 9 = 333 37 x 12 = 444 37 x 15 = 555 37 x 18 = 666 37 x 21 = 777 37 x 24 = 888 37 x 27 = 999 (Note: 37 is multiplied by the table of 3)

THIRD: WHAT A BEAUTIFUL RESULT

a) Think a number less than 10 b) Multiply it by 3 c) Add 1 in the product d) Again multiply it by 3 e) Then add the number you thought in the beginning f) Conclusion: You see, in ones place is always 3 and in tens place is the number you thought --- Let us confirm the rule by the following example: a) Suppose I think 8 b) 8 x 3 = 24 c) 24 + 1 = 25 d) 25 x 3 = 75 e) 75 + 8 = 83

FOURTH: MULTIPLY BY 4 2 1 9 7 8 x 4 = 8 7 9 1 2 (You see, the numbers are reversed - do you know, why?)

FIFTH: 20 BIRDS 20 DOLLARS

1 sparrow costs 25 cents 1 pigeon costs 50 cents 1 dove costs 4 dollars John wants to buy 20 birds for 20 dollars. What should he do? Answer: 3 doves for $ 12.00 15 pegeons for $ 7.50 2 sparrows for $ 0.50 Total: 20 birds $ 20.00

FIND OUT THE WEEKDAY OF A GIVEN CALENDAR DATE:

CHART I - Specific numbers of calandar months: Jan 1 Feb 4 Mar 4 Apr 0 May 2 Jun 5 Jul 5 Aug 3 Sep 6 Oct 1 Nov 4 Dec 6

CHART II - Specific numbers of seven days: Sun 1 Mon 2 Tue 3 Wed 4 Thu 5 Fri 6 Sat 0

Example: What was the weekday on "14th Aug 1947" First Step: Divide 47 by 4 (4 is constant) The quotient is 11 and remainder is 3. Second Step: Ignore the remainder and add 47 and quotient: 47 + 11 = 58 Third Step: See the Chart I, specific number of Aug is 3, add it: 58 + 3 = 61 Fourth Step: Add 14: 61 + 14 = 75 Fifth Step: Divide 75 by 7 (because of 7 days a week): Remainder is 5 Sixth Step: See the chart II Solution: Thursday Now, find out the weekday of your date of birth. NOTE: This formula can be applied for the years from 1900 to 1999

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